Determine a sample size with confidence level of 95% that will show the true proportion of population ?
Margin of error at 95% confidence = 0.98/鈭歯
0.98/鈭歯 = 卤0.02
0.98 = 卤.02 鈭歯
鈭歯 = 卤49
n = 2401Determine a sample size with confidence level of 95% that will show the true proportion of population ?
Curious on the solution approach.... where is the total population of 60000 considered ?
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